https://phys.org/news/2018-09-simulation-nuclear-pasta-billion-harder.html

Because of the immense gravity of neutron stars, the outer layers freeze solid to form a crust that surrounds a liquid core. Between the outer layer and the inner core quark–gluon plasma (or quark soup) nuclear pasta forms at matter densities of 10^14 g/cm^3. Protons and neutrons are thought to spatially separate as nuclear attraction and Colombic repulsion forces compete (a type of Spinodal decomposition) and end up forming long cylindrical shapes or flat planes. These have become known as “spaghetti” and “lasagne”—or nuclear pasta.

In a recent PRL paper, it was claimed that this nuclear pasta has a stength of 10 billion times that of steel.

https://journals.aps.org/prl/abstract/10.1103/PhysRevLett.121.132701

The paper states in abstract a strength of 10^30 ergs/cm^3. 1 erg / cm^3 is equivalent to 0.1 J/m^3. 0.1 J/m^3 is the same as 0.1 Pa. Therefore 10^30 ergs/cm^3 is 10^29 Pa.

Comparing this to the 5.5 GPa stength of Steel Scifer wires… ultimate shear strength = 0.5 * UTS = 2.25 GPa.

(A value for maximum theoretical Shear strength would be 12 GPa I believe).

So now …. 10^29 Pa / 2.25^9 Pa = 3.0 x 10^19 * steel strength = 30.25 Quintillion times the strength of steel.

Tell me what I’m missing here… maybe the paper converted to specific strength over exaggerate their value? What’s the density of nuclear pasta?

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