An FIA rally-cross car can accelerate from 0-60 mph in 2 seconds.

Lets check equations of motion, first some definitions.

u – initial velocity

v – final velocity

a – acceleration

t – time

s – displacement

v = u + at

s = ut + ½at2

v^{2}= u^{2}+ 2as

BBC Bitesize resource on equations of motion.

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v is 60 mph is 26.8224 m/s

and average acceleration = 26.8224 / 2 = 13.4112 m/s^2

= 13.4112 / 9.80665 g

= 1.368 g

~ 1.4 g

Back calculating….

v = u + at

v = 0 + 13.4112 * 2

OK, in agreement with what we expected.

Distance travelled

s = ut + 1/2 * a t^{2}

= 0 + 0.5 * 13.4112 * 4

= 2 * 13.4112

= 26.8224 m

~ 26.8 m

Filed under: cars, mathematics, Maths

moyebodeteacher, on 5 April, 2016 at 8:15 am said:Reblogged this on DT & Engineering Teaching & Learning Blog and commented:

Interesting article on g-force when a rally car is accelerating…